An interactive simulation drawing a tree, its shadow, and a matching right-angled triangle. At 22.5° (π/8), the shadow-to-height ratio L/H equals tan(22.5°) = √2 − 1 ≈ 0.41421356. Use the "Sun Motion" button to change the angle, "Measure" to show H, L, and L/H on the canvas, and "Reset" to return to 22.5°.

🌳 Tree of Unification · Tree Above · Triangle Below

The θ arc matches above and below — measured from the vertical, not the horizontal

This page presents the interactive visual simulation of the mathematical identity tan(22.5°) = √2 − 1 ≈ 0.41421356. The exploratory field study (n=5) reported an initial numerical similarity, further explored in the Measurement Protocol.
🌐 العربية 🌳 Tree 🌲 Tree 3 🏛️ Geometry 📏 Field Report 1. Frame1 2. Frame2 3. Frame3 4. Frame4 Bridge
Angle θ (from vertical)22.5°
L / H (Shadow ÷ Height)0.41421356
tan(θ)0.41421356
√2 − 1 (Reference)0.41421356
v4.1: Calculation fixed in the proof section; the sun freezes at the current angle; the sun is clamped within the canvas.
Only at θ = 22.5°: L/H = √2 − 1 = 0.41421356

🥭 Pilot field study

A preliminary measurement on a small sample of Yemeni mango trees (n = 5 mango out of 30 trees in the survey) gave a mean (H−h)/H ≈ 0.41297, which is close to tan(22.5°) = 0.4142. This is an exploratory result pointing to an interesting numerical similarity; it requires independent verification before any generalization.

📏 See the protocol and data in (tree3-en)

📐 Three levels of interpretation — do not conflate them

This page combines three distinct epistemic layers: an exact mathematical identity, a numerical visual simulation, and a pilot field study. Keeping them separate strengthens credibility and does not detract from the project's value.

Level 1 — Mathematical identity (exact)

The number √2−1 is not a choice; it is an exact consequence of the half-angle formula:

tan(22.5°) = tan(45° / 2)
= (1 − cos 45°) / sin 45°
= (1 − √2/2) / (√2/2)
= (2 − √2) / √2
= √2 − 1 ≈ 0.4142135624

This is a mathematical identity — valid regardless of any tree or shadow.

↓

Level 2 — Numerical simulation: Pythagoras applied

The following example is independent and illustrative (at ≈ 56.54°): it shows how Pythagoras links the sides of a right triangle. The numbers are not from the current drawing (θ=22.5°); they were chosen to illustrate the application.

Z = 192, C = 290.74

Z² + C² = 192² + 290.74²
         = 36864 + 84530.74
         = 121394.74
A = √121394.74 ≈ 348.42

tan⁻¹(290.74 / 192) ≈ 56.54°

In the default simulation (θ=22.5°), the ratio L/H becomes tan(22.5°) = √2−1 automatically — see it at the top of the page.

↓

Level 3 — Pilot field study

A preliminary measurement on a small sample of Yemeni mango trees gave a mean (H−h)/H close to the theoretical value:

n_mango = 5 (out of 30 trees)
mean (H−h)/H = 0.41297
TOST p = 0.000801 (preliminary)
90% CI = [0.40491, 0.42102]

Inference limits: the sample is small; the mean indicates a numerical similarity with the mathematical identity, not proof of a general natural law for trees. Results are exploratory and require independent verification before any generalization.

Conclusion: each level serves its purpose

Z' + C' + A' = 1

where Z' = Z/(Z+C+A), C' = C/(Z+C+A), and A' = A/(Z+C+A).
Z and C are the Pythagorean legs, A is the hypotenuse. This is a normalized representation, not a direct consequence of Pythagoras alone.

Level 1 gives the exact value — Level 2 shows it visually — Level 3 suggests a preliminary numerical similarity.